A coin is tossed three times find the probability of receiving head more times than tail

1. \(\dfrac 1 4\)
2. \(\dfrac1 8\)
3. \(\dfrac 1 2\)
4. \(\dfrac 3 8\)

Answer (Detailed Solution Below)

Option 1 : \(\dfrac 1 4\)

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Electric charges and coulomb's law (Basic)

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Concept:

The probability of the occurrence of an event A, out of total possible outcomes N, is given by P(A) = \(\rm \dfrac{n(A)}{N}\), where n(A) is the number of ways in which the event A can occur.

Calculation:

The total number of different possible outcomes (N) in tossing a coin 3 times is 23 = 8.

For getting a head and a tail alternately, the possibilities are HTH, THT → 2 possibilities n(A).

∴ Required probability = \(\rm \dfrac{n(A)}{N}=\dfrac{2}{8}=\dfrac{1}{4}\)

The possible set of A coin is tossed 3 times is {HHH}{HHT}{HTH}{HTT}{TTT}{TTH}{THT}{THH} = 8

The probability of getting a head and a tail alternately is {HTH}{THT} = 2

So, required probability = \(\rm \dfrac{n(A)}{N}=\dfrac{2}{8}=\dfrac{1}{4}\)

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Again, welcome to a new problem. I was still working on probability theory. We are dealing with probability theory. Assuming it's a fair coin, the probability of having heads is one half and the probability of having a tail is one half. If you're dealing with a fair coin and you're closing your head or tail, then the probabilities can be compounded, so for the most part we can use tree diagrams. What is the probability of getting ahead or getting the tales when you see it? That means you're adding probabilities. You can say what's the probability of getting ahead and getting a tail. Assuming the events are independent, you have independent events. He was saying that we are making certain assumptions in this particular problem. If you choose the coin, the probability of finding at least one head will be determined by how many times the coin is thrown. This is a very big deal. Remember when we said to always think about summing up the probabilities, or at least one tail? We're doing those two things. We want to find out if we get at least one head or one tail if we toss a coin three times. This is what's happening right here. We're talking about probability theories. You can either get a head or tail if you use a tree diagram the first time you toss a coin. There was a chance of getting ahead. Getting a story is one half. We can go ahead and do the same thing again if this is the first dose. This is the second toss choice number two and we have another chance after that. We have a chance the third time. We're going to toss it three times. Task number three is this one. If you follow the tree, you will see that there is a chance that the head had three heads and then it was tail head. You could see we were going that way and then we had head tail. You have a head, a tail, and then we have a tail. The head tail is long. We have tail tail head and taylor taylor. The probability of at least one head is the same as the probability of all heads, which is one minus the probability of all heads. The probability of having three heads is an eighth. One head is actually one minus. Let's get that back. One minus all the stories. It's the compliment of all tales and the chance of getting all tales. I don't know why. This isn't tails. The probability of getting at least one tale is the same as getting all heads. This is minus one and minus one and minus one and minus one and minus one and minus one and minus one and minus two and minus two and minus two and minus two and minus two and minus two and minus two and minus two and minus two and minus two and minus two and minus two The probability of getting at least one head is one of these two. The probabilities are 7 and 7 plus 7. We're having a problem now. We're having a problem now. It is possible to get at least one head or at least one tail. If we can get some of these two, we can sum them up because you can't have a chance of being between zero and one. The probability of having at least one head will be 7. We could stop and then the probability of loving at least until seven of the adults are present. It's not gonna be possible because you're summing them up like this. These are the two solutions that you're looking at. There was a problem where we were looking for probabilities. If you chose a coin three times, what's the probability of finding at least one head? We had all these heads. We had head, head, tail, head, tail head. The chance of finding all heads was one of the eight. The stories were one of the eight. We got the compliment for each one of these to show that there is a good chance of finding a head. Hopefully you enjoy the problem. Have a wonderful day, and send any questions or comments.

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